document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271186>Question 271186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1 number is 4 less than 3 times another.  If their sum is increased by 5, the result is 25.  Find the numbers.   <BR>\n" );
document.write( "The numbers are 6 & 14 - how did they get 6, I can figure out 14 but missing an essential part. <BR>\n" );
document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198577 by </B><A HREF=/tutors/aboutme.mpl?userid=craigt><B>craigt(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=craigt><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two numbers, x & y<BR>\n" );
document.write( "y=3x-4<BR>\n" );
document.write( "x + y + 5 = 25<BR>\n" );
document.write( "x + 3x - 4 + 5 = 25<BR>\n" );
document.write( "4x +1 = 25<BR>\n" );
document.write( "4x = 24<BR>\n" );
document.write( "x = 6, So one of the numbers is 6, now solve for y<BR>\n" );
document.write( "y = 3x-4 = 3(6)-4 = 14\r<BR>\n" );
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document.write( " </SPAN>\n" );
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