document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271060>Question 271060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> CAn someone please help me? I keep trying these but I also keep getting different answers:(\r<BR>\n" );
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document.write( "a) [16^(1/2) +(2/3)^0]^-2<BR>\n" );
document.write( "b)(27/8)^(1/3) + 4^-1<BR>\n" );
document.write( "c)(7^0 - 4^-1)^-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198556 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Remember any number raised to the power of 0 = 1<BR>\n" );
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document.write( "a) [16^(1/2) +(2/3)^0]^-2\r<BR>\n" );
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document.write( "[16^(1/2) + 1]^-2<BR>\n" );
document.write( "The exponent of 1/2 is the square root of the number<BR>\n" );
document.write( "(4 + 1)^-2<BR>\n" );
document.write( "5^-2<BR>\n" );
document.write( "The reciprocal gets rid of the neg<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F5%5E2 ALIGN=MIDDLE  ALT=\"1%2F5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F25 ALIGN=MIDDLE  ALT=\"1%2F25\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
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document.write( "b)(27/8)^(1/3) + 4^-1<BR>\n" );
document.write( "Take the cube root of both numerator and denominator<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F2 ALIGN=MIDDLE  ALT=\"3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F4 ALIGN=MIDDLE  ALT=\"6%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%2F4 ALIGN=MIDDLE  ALT=\"7%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "c)(7^0 - 4^-1)^-3<BR>\n" );
document.write( "(1 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >)^-3 = (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F4 ALIGN=MIDDLE  ALT=\"3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >)^-3 = (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3 ALIGN=MIDDLE  ALT=\"4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >)^3<BR>\n" );
document.write( "cube both the numerator and denominator<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=64%2F27 ALIGN=MIDDLE  ALT=\"64%2F27\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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