document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271152>Question 271152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the larger of two numbers is divided by 6 and is subtracted from three times the smaller number, the result is 44. If the smaller number is increased by 4, the result is half the largest number. Find the numbers. This is so comples I do not know how to set it up.  I know 3X-n/6=44    and the part  +4 = 1/2n </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198552 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Numbers N and n<BR>\n" );
document.write( "Then 3n - (N/6)= 44<BR>\n" );
document.write( "and (n + 4)= N/2<BR>\n" );
document.write( "so (n+4)/3 = N/6<BR>\n" );
document.write( "so 3n - (n + 4)/3 = 44<BR>\n" );
document.write( "9n - n - 4 = 132<BR>\n" );
document.write( "8n = 136<BR>\n" );
document.write( "n = 17<BR>\n" );
document.write( "N = 42<BR>\n" );
document.write( " </SPAN>\n" );
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