document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271148>Question 271148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rachel allows herself 1 hr to reach a sales appointment 50 mi away. After she has driven 30 mi, she realizes she must increase her speed by 15 mph in order to get there on time. What was her speed for the first 30 mi? I cannot familiarize this problem and it's driving me nuts. I am taking an online course and it's hard. I have tried to come up with a formula... If she travels x miles per hour for 30 miles and x+15 miles per hour for 20 miles she would get there in 60 mins, or one hour. x+x+15=50? wait miles per hour is distance/time. so 50 miles / 1hour. and she travels at x for 30 so 30 times x? I am so lost on this problem. I have tried a bunch more ways that don't make sense. Once i got x=1. She obviously did not travel at one mile per hour or she would never had made it 50 miles in one hour! It would be so much more funny if I wasn't dying over this problem! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198550 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rachel allows herself 1 hr to reach a sales appointment 50 mi away. After she has driven 30 mi, she realizes she must increase her speed by 15 mph in order to get there on time. What was her speed for the first 30 mi? \r<BR>\n" );
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document.write( "FIRST HALF HOUR\r<BR>\n" );
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document.write( "let the speed she travelled for the first half hour be x mph<BR>\n" );
document.write( "distance traveled in the first half hour will be 1/2 * x  MILES\r<BR>\n" );
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document.write( "SECOND HALF HOUR\r<BR>\n" );
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document.write( "SPEED FOR THE NEXT HALF HOUR WAS X+15 MPH\r<BR>\n" );
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document.write( "DISTANCE TRAVELLED WILL BE (X+15) *1/2  miles\r<BR>\n" );
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document.write( "the total distance she traveled was 50 miles\r<BR>\n" );
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document.write( "1/2*x + 1/2*(x+15) =50\r<BR>\n" );
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document.write( "x+x+15 = 2*50\r<BR>\n" );
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document.write( "2x= 100-15\r<BR>\n" );
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document.write( "x=85/2 = 42.5 mph.    In the second half hour it will be 42.5 +15 = 57.50 mph\r<BR>\n" );
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document.write( "Confirmation :\r<BR>\n" );
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document.write( "First half hour she travels 21.25 miles. In the second half hour she travels 28.75 miles.\r<BR>\n" );
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document.write( "the sum of these two is 50 miles.\r<BR>\n" );
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document.write( "Hope it is clear\r<BR>\n" );
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document.write( "Have fun with Math\r<BR>\n" );
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document.write( " </SPAN>\n" );
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