document.write( "Question 271150: Please help me solve this equation: \r
\n" );
document.write( "\n" );
document.write( "Here's what I have tried:
\n" );
document.write( "LCM: (a+3)(a+1)
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "and then I got stuck. Did I do something wrong somewhere? I see that I can factor out a on the left side, but I'm supposed to be solving for a. So if I factor out a I'm still left with a(a+7) and to solve for a I would have to divide by 7? Don't I have to divide All terms on the left by 7 then? Maybe I'm just getting too tired but I really don't know what to do next. I would really appreciate a nudge in the right direction. I forgot to say thank you in advance on my last question, so Thanks in advance on this one and the last one.\r
\n" );
document.write( "\n" );
document.write( "~Kendra~ \n" );
document.write( "
Algebra.Com's Answer #198549 by Greenfinch(383)![]() ![]() You can put this solution on YOUR website! Minor sign problem I think. \n" ); document.write( "a^2 + 7a -3 = -9 not +3 \n" ); document.write( "a^2 + 7a +6 = 0 \n" ); document.write( "(a + 6)(a + 1) = 0 \n" ); document.write( "a = -6 or -1 \n" ); document.write( " |