document.write( "Question 271150: Please help me solve this equation: \"%283a-5%29%2F%28a%5E2%2B4a%2B3%29%2B%282a%2B2%29%2F%28a%2B3%29=%28a-3%29%2F%28a%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "Here's what I have tried:
\n" ); document.write( "LCM: (a+3)(a+1)
\n" ); document.write( "\"%283a-5%29%2F%28a%2B3%29%28a%2B1%29%D7%28a%2B3%29%28a%2B1%29=3a-5\"
\n" ); document.write( "\"%282%28a%2B1%29%29%2F%28a%2B3%29%D7%28a%2B3%29%28a%2B1%29=2%28a%2B1%29%5E2\"
\n" ); document.write( "\"%28a-3%29%2F%28a%2B1%29%D7%28a%2B3%29%28a%2B1%29=%28a-3%29%28a%2B3%29=a%5E2-9\"
\n" ); document.write( "\"3a-5%2B2%28a%5E2%2B2a%2B1%29=a%5E2-9\"
\n" ); document.write( "\"3a-5%2B2a%5E2%2B4a%2B2=a%5E2-9\"
\n" ); document.write( "\"2a%5E2%2B7a-3=a%5E2-9\"
\n" ); document.write( "\"2a%5E2-a%5E2%2B7a-3=a%5E2-a%5E2-9\"
\n" ); document.write( "\"a%5E2%2B7a%2B3=-9\"
\n" ); document.write( "\"a%5E2%2B7a%2B3-3=-9-3\"
\n" ); document.write( "\"a%5E2%2B7a=-12\"
\n" ); document.write( "and then I got stuck. Did I do something wrong somewhere? I see that I can factor out a on the left side, but I'm supposed to be solving for a. So if I factor out a I'm still left with a(a+7) and to solve for a I would have to divide by 7? Don't I have to divide All terms on the left by 7 then? Maybe I'm just getting too tired but I really don't know what to do next. I would really appreciate a nudge in the right direction. I forgot to say thank you in advance on my last question, so Thanks in advance on this one and the last one.\r
\n" ); document.write( "\n" ); document.write( "~Kendra~
\n" ); document.write( "

Algebra.Com's Answer #198549 by Greenfinch(383)\"\" \"About 
You can put this solution on YOUR website!
Minor sign problem I think.
\n" ); document.write( "a^2 + 7a -3 = -9 not +3
\n" ); document.write( "a^2 + 7a +6 = 0
\n" ); document.write( "(a + 6)(a + 1) = 0
\n" ); document.write( "a = -6 or -1
\n" ); document.write( "
\n" );