document.write( "Question 271142: In 2000, my husband John was eleven times as old as my son William. In 2012, he will be three times as old as my son. How old was my son of 2000? \n" ); document.write( "
Algebra.Com's Answer #198542 by Greenfinch(383)\"\" \"About 
You can put this solution on YOUR website!
William's age in 2000 is x so John age in 2000 is 11x
\n" ); document.write( "In 2012, Williams is x + 12, John is 11x + 12
\n" ); document.write( "We are told 3(x + 12) = 11x + 12
\n" ); document.write( "3x + 36 = 11x + 12
\n" ); document.write( "8x = 24
\n" ); document.write( "x = 3
\n" ); document.write( "In 2000 ages were 3 and 33
\n" ); document.write( "In 2012 ages will be 15 and 45 (which is 3 times)
\n" ); document.write( "
\n" );