document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33471>Question 33471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2(3x2+X+2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19853 by </B><A HREF=/tutors/aboutme.mpl?userid=mszlmb><B>mszlmb(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mszlmb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mszlmb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> check 4 problems on my part\r<BR>\n" );
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document.write( "is this even ur equation?? <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%283X%5E2%2BX%2B2%29 ALIGN=MIDDLE  ALT=\"2%283X%5E2%2BX%2B2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "if its not then repost or sumthin cuz that's what im solving :oD<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%283X%5E2%2BX%2B2%29 ALIGN=MIDDLE  ALT=\"2%283X%5E2%2BX%2B2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > let's solve by factoring.<BR>\n" );
document.write( "A=3, B=1, C=2. (because the linear formula is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Ax%5E2%2BBx%2BC ALIGN=MIDDLE  ALT=\"Ax%5E2%2BBx%2BC\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<BR>\n" );
document.write( "yea, we R gonna ignore the 2 in front 4 now.<BR>\n" );
document.write( "now we do A*C.  3*2 is 6. now we need find 2 numbers that multiply 2 6 and add to B, 1.  simply enough, our numbers are -2 and 3.  but we have a problem.  -2 and 3 don't multiply to 6, they multiply to negative 6.  we're going to do this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%283X%5E2%2BX%2B2%29 ALIGN=MIDDLE  ALT=\"2%283X%5E2%2BX%2B2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is our equation.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%283X%5E2%2BX-2%2B4%29 ALIGN=MIDDLE  ALT=\"2%283X%5E2%2BX-2%2B4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the same thing, let's disregard the 4 for now. let's focus on <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%5E2%2BX-2 ALIGN=MIDDLE  ALT=\"3x%5E2%2BX-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  it's the same as saying <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%5E2%2B3x-2x-2 ALIGN=MIDDLE  ALT=\"3x%5E2%2B3x-2x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, is it not (yea, it is)..  ok so now we look for things we can factor.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%5E2+and+3x ALIGN=MIDDLE  ALT=\"3x%5E2+and+3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > have a similarity: 3x.  So we're going to factor the 3x out.  It thence becomes 3x(x+1).  now we factor -2x-2.  Take a wild guess..  YES!  The common factor is -2!  we factor -2x-2 to obtain -2(x+1).<BR>\n" );
document.write( "ok so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3X%5E2%2BX-2 ALIGN=MIDDLE  ALT=\"3X%5E2%2BX-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the same as 3x(x+1)-2(x+1) .  Now put the x+1's together and what's left?  3x-2.  You have factored <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%5E2%2B3x-2x-2 ALIGN=MIDDLE  ALT=\"3x%5E2%2B3x-2x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > into <BR>\n" );
document.write( "(3x-2)(x+1). Let's see the entire equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28%283x-2%29%28x%2B1%29%2B4%29 ALIGN=MIDDLE  ALT=\"2%28%283x-2%29%28x%2B1%29%2B4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > how do we take that annoying +4 out of there?  well it would be 8 outside the parenthises, wouldn't it?  (because 2(4)=8).  <BR>\n" );
document.write( "our equation is upgraded to 2(3x-2)(x+1)+8.<BR>\n" );
document.write( "Now we have a split; either your equation is f(x)=2(3x-2)(x+1)+8 , or 0=2(3x-2)(x+1)+8.<BR>\n" );
document.write( "f(x)=2(3x-2)(x+1)+8:<BR>\n" );
document.write( "   There are an infinite amount of answers, I'm quite certain, because you are naming a function: an entire infinite graph.<BR>\n" );
document.write( "0=2(3x-2)(x+1)+8<BR>\n" );
document.write( "   This is simpler, and has an answer. We begin with <BR>\n" );
document.write( "0=2(3x-2)(x+1)+8<BR>\n" );
document.write( "-8=2(3x-2)(x+1)<BR>\n" );
document.write( "-4=(3x-2)(x+1)<BR>\n" );
document.write( "0=(3x-2)(x+1)+4<BR>\n" );
document.write( "this turns out yet another parabola:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%283x-2%29%28x%2B1%29%2B4%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%283x-2%29%28x%2B1%29%2B4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "I'm sorry if I'm not more help.  If you find that I'm wrong please tell me so I can learn this.  THNX!<BR>\n" );
document.write( "ps I really recommend talking 2 ur teacher about this as it is hard to explain without pen and paper.<BR>\n" );
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