document.write( "Question 270937: 6x^7y^5/3x^-1 \n" ); document.write( "
Algebra.Com's Answer #198509 by JenniferTutors(83)\"\" \"About 
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For this equation:\r
\n" ); document.write( "\n" ); document.write( "\"6x%5E7y%5E5%2F3x%5E-1\"\r
\n" ); document.write( "\n" ); document.write( "First you cannot have a negative exponent in an equation, so on the denominator: \"3x%5E-1\" Move the x to the numerator to make it positive. You would only take the x and not the 3 because it is attached to the exponent.\r
\n" ); document.write( "\n" ); document.write( "It would look as follows:\r
\n" ); document.write( "\n" ); document.write( "\"6x%5E8y%5E5%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Notice how the exponents increased from \"6x%5E7\" to \"6x%5E8\"\r
\n" ); document.write( "\n" ); document.write( "Next you can simplify that 3 goes into 6 twice so you're left with a 1 on the denominator:\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E8y%5E5\"\r
\n" ); document.write( "\n" ); document.write( "Left with your answer.
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