document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271088>Question 271088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> OK, so I know the following is incorrect, so could you help me to figure out what I am doing wrong. I am trying to solve the linear equations by using linear combinations.\r<BR>\n" );
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document.write( "9X-3Z=20<BR>\n" );
document.write( "3X+6Z=2\r<BR>\n" );
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document.write( "My answers were X=2 and Z= -.66 or -2/3\r<BR>\n" );
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document.write( "I would appreciate your help!\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198489 by </B><A HREF=/tutors/aboutme.mpl?userid=LarissaRichardson><B>LarissaRichardson(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LarissaRichardson><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LarissaRichardson><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9x-3z=20<BR>\n" );
document.write( "3x+6z=2\r<BR>\n" );
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document.write( "A.Choose a variable to eliminate first. In this example, y will be eliminated.\r<BR>\n" );
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document.write( "B. Multiply the equations so that there is the same number of that variable in both equations. Find the least common multiple (LCM) of the coefficients of the variable you chose to eliminate. Multiply the equations accordingly so that both of the coefficients are of the same value, except one is negative.<BR>\n" );
document.write( "The LCM would be six seen as 3x+6z=2 and six is the LCM<BR>\n" );
document.write( "Multiply first equation by two.<BR>\n" );
document.write( "2(9x-3z=20)<BR>\n" );
document.write( "18x-6z=40\r<BR>\n" );
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document.write( "C. Now add the equations leaving out the variable with z in it.\r<BR>\n" );
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document.write( " 18x-6z=40<BR>\n" );
document.write( "+3x+6z=2<BR>\n" );
document.write( "___________<BR>\n" );
document.write( "21x=42<BR>\n" );
document.write( "x=2\r<BR>\n" );
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document.write( "D.  Solve for the remaining variable. This can be done using any methods to solve for a one-variable equation.<BR>\n" );
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document.write( "9(2)-3z=20<BR>\n" );
document.write( "18-3z=20<BR>\n" );
document.write( "-3z=2<BR>\n" );
document.write( "z=-2/3\r<BR>\n" );
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document.write( "I believe you said you had the same answer so I don't know why you say it's wrong. </SPAN>\n" );
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