document.write( "Question 271003: A jet flew at an average speed of 520 miles per hour from Metro City to Farmville. Because of a favorable tail wind, the jet averaged 600 on the return trip, and the return trip was shortened by 40 minutes. How far is it from Metro City to Farmville? \n" ); document.write( "
Algebra.Com's Answer #198462 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
write equations for each trip
\n" ); document.write( "(1) \"d%5B1%5D+=+r%5B1%5D%2At%5B1%5D\"
\n" ); document.write( "(2) \"d%5B2%5D+=+r%5B2%5D%2At%5B2%5D\"
\n" ); document.write( "given:
\n" ); document.write( "\"d%5B1%5D+=+d%5B2%5D\" (call it \"d\")
\n" ); document.write( "\"r%5B1%5D+=+520\" mi/hr
\n" ); document.write( "\"r%5B2%5D+=+600\" mi/hr
\n" ); document.write( "\"t%5B2%5D+=+t%5B1%5D+-+2%2F3\" hr (40 min is 2/3 hr)
\n" ); document.write( "---------------------------------------------
\n" ); document.write( "(1) \"d+=+520%2At%5B1%5D\"
\n" ); document.write( "(2) \"d+=+600%2A%28t%5B1%5D+-+2%2F3%29\"
\n" ); document.write( "they both equal \"d\", so
\n" ); document.write( "\"520t%5B1%5D+=+600t%5B1%5D+-+400\"
\n" ); document.write( "\"80t%5B1%5D+=+400\"
\n" ); document.write( "\"t%5B1%5D+=+5\" hrs
\n" ); document.write( "And, from (1)
\n" ); document.write( "\"d+=+520%2At%5B1%5D\"
\n" ); document.write( "\"d+=+520%2A5\"
\n" ); document.write( "\"d+=+2600\" mi
\n" ); document.write( "They are 2600 miles from eachother
\n" ); document.write( "check answer:
\n" ); document.write( "(2) \"d+=+600%2A%28t%5B1%5D+-+2%2F3%29\"
\n" ); document.write( "\"d+=+600%2A%284+%2B+1%2F3%29\"
\n" ); document.write( "\"d+=+2400+%2B+200\"
\n" ); document.write( "\"d+=+2600\" mi
\n" ); document.write( "OK
\n" ); document.write( "
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