document.write( "Question 270996: Find a general form of an equation of the line that is tangent to the circle at the point P.
\n" ); document.write( "x 2 + y 2 = 100; P ( 8, 6 )
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Algebra.Com's Answer #198447 by drk(1908)\"\" \"About 
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We have a circle with radius 10 centered at (0,0) and passing through (8,6).
\n" ); document.write( "The slope of (0,0) and (8,6) is
\n" ); document.write( "\"m+=+3%2F4\"
\n" ); document.write( "but we want the perpendicular slope for the tangent line as
\n" ); document.write( "\"+m+=+_4%2F3\"
\n" ); document.write( "---
\n" ); document.write( "The equation is expressed as
\n" ); document.write( "\"y+=+mx+%2B+b\"
\n" ); document.write( "and putting in our slope, -4/3 and point, (8,6) we get
\n" ); document.write( "\"6+=+%28-4%2F3%29%2A8+%2B+b\"
\n" ); document.write( "which is
\n" ); document.write( "\"6+=+-32%2F3+%2B+b\"
\n" ); document.write( "and then
\n" ); document.write( "\"b+=+50%2F3\"
\n" ); document.write( "The answer is
\n" ); document.write( "\"y+=+%28-4%2F3%29x+%2B+50%2F3\"
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