document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=271027>Question 271027</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Paul has some 50 cents and $2 coins. The total value of the coins is $8. If there are 7 coins altogether, how many coins of each kind does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198440 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198440\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Paul has some 50 cents and $2 coins. The total value of the coins is $8. If there are 7 coins altogether, how many coins of each kind does he have?<BR>\n" );
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document.write( "Value Eq: 50f + 200t = 800 cents<BR>\n" );
document.write( "Quantity Eq: f + t = 7<BR>\n" );
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document.write( "Solve for \"f\"; substitute and solve for \"t\":<BR>\n" );
document.write( "f = 7-t<BR>\n" );
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document.write( "50(7-t) + 200t = 800<BR>\n" );
document.write( "350 - 50t + 200t = 800<BR>\n" );
document.write( "150t = 450<BR>\n" );
document.write( "t = 3 (# of $2.00 coins)<BR>\n" );
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document.write( "Since f+t = 7, f = 4 (# of 50 cent coins)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );