document.write( "Question 271027: Paul has some 50 cents and $2 coins. The total value of the coins is $8. If there are 7 coins altogether, how many coins of each kind does he have? \n" ); document.write( "
Algebra.Com's Answer #198433 by drk(1908)\"\" \"About 
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(i) \"f+%2B+d+=+7\"
\n" ); document.write( "(ii) \".50f+%2B+2d+=+8\"
\n" ); document.write( "step 1 - multiply (ii) by 10 to get
\n" ); document.write( "(iii) \"5f+%2B+20d+=+80\"
\n" ); document.write( "step 2 - multiply (i) by -5 to get
\n" ); document.write( "(iv) \"-5f+-+5d+=+-35\"
\n" ); document.write( "step 3 - add (ii) and (iv) to get
\n" ); document.write( "(v) \"15d+=+45\"
\n" ); document.write( "step 4 - divide by 15 to get
\n" ); document.write( "(vi) \"d+=+3\"
\n" ); document.write( "This means that
\n" ); document.write( "\"f+=+4\"
\n" ); document.write( "-------
\n" ); document.write( "There are 4, 50 cent coins and 3, 2 dollar coins
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