document.write( "Question 33460: log x/n=log(x^1/n) \n" ); document.write( "

Algebra.Com's Answer #19843 by mukhopadhyay(490) $\"\"$ $\"About$

You can put this solution on YOUR website!
log x/n=log(x^1/n)
\n" ); document.write( "=> log x - log n = 1/n log x
\n" ); document.write( "=> log x - 1/n log x = log n
\n" ); document.write( "=> log x (1-1/n) = log n
\n" ); document.write( "=> log x = [n/(n-1)]*log n
\n" ); document.write( "=> x = 10^[(n/n-1)log n] \n" ); document.write( "

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