document.write( "Question 270807: The following table shows the amount of polonium in milligrams remaining after x days from an original sample of 2 milligrams.
\n" ); document.write( "x(days) 0 100 200 300
\n" ); document.write( "y milligrams 2 1.22 0.743 0.453\r
\n" ); document.write( "\n" ); document.write( "a. is the half life pf te polonium less than 200 days?
\n" ); document.write( "b. give a general formula thatr can be used to approximate the amount A of polonium after x days.
\n" ); document.write( "c. what is the half-life of the polonium? GRaph A(x) and show th epoint that would show the half-life for x=2 milligrams.
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Algebra.Com's Answer #198336 by ankor@dixie-net.com(22740)\"\" \"About 
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The following table shows the amount of polonium in milligrams remaining after x days from an original sample of 2 milligrams.
\n" ); document.write( "x(days) 0 100 200 300
\n" ); document.write( "y milligrams 2 1.22 0.743 0.453
\n" ); document.write( ":
\n" ); document.write( "a. is the half life of the polonium less than 200 days?
\n" ); document.write( "Find the half life (h) using values for 100 days and resulting amt of 1.22 mg
\n" ); document.write( "2*(2^(-100/h)) = 1.22
\n" ); document.write( ":
\n" ); document.write( "2^(-100/h) = \"1.22%2F2\"
\n" ); document.write( ";
\n" ); document.write( "2^(-100/h) = .61
\n" ); document.write( ":
\n" ); document.write( "log(2^(-100/h)) = log(.61)
\n" ); document.write( "\"-100%2Fh\"log(2) = log(.61)
\n" ); document.write( "\"-100%2Fh\"= \"log%28.61%29%2Flog%282%29\"
\n" ); document.write( "\"-100%2Fh\" = -.713
\n" ); document.write( "h = \"100%2F.713\"
\n" ); document.write( "h ~ 140 days is the half life
\n" ); document.write( ":
\n" ); document.write( "b. give a general formula that can be used to approximate the amount A of polonium after x days.
\n" ); document.write( "A = 2*2^(-x/140)
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "c. what is the half-life of the polonium?
\n" ); document.write( "we found it to be 140 days in (a)
\n" ); document.write( ":
\n" ); document.write( " GRaph A(x) and show th epoint that would show the half-life for x=2 milligrams.
\n" ); document.write( "Graph the equation y = 2*2^(-x/140)
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-50%2C+325%2C+-1%2C+3%2C+2%2A2%5E%28-x%2F140%29%29+\"
\n" ); document.write( "You can see that at 140 days there is about 1 mg of the substance
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