document.write( "Question 270807: The following table shows the amount of polonium in milligrams remaining after x days from an original sample of 2 milligrams.
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document.write( "x(days) 0 100 200 300
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document.write( "y milligrams 2 1.22 0.743 0.453\r
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document.write( "a. is the half life pf te polonium less than 200 days?
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document.write( "b. give a general formula thatr can be used to approximate the amount A of polonium after x days.
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document.write( "c. what is the half-life of the polonium? GRaph A(x) and show th epoint that would show the half-life for x=2 milligrams. \n" );
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Algebra.Com's Answer #198336 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The following table shows the amount of polonium in milligrams remaining after x days from an original sample of 2 milligrams. \n" ); document.write( "x(days) 0 100 200 300 \n" ); document.write( "y milligrams 2 1.22 0.743 0.453 \n" ); document.write( ": \n" ); document.write( "a. is the half life of the polonium less than 200 days? \n" ); document.write( "Find the half life (h) using values for 100 days and resulting amt of 1.22 mg \n" ); document.write( "2*(2^(-100/h)) = 1.22 \n" ); document.write( ": \n" ); document.write( "2^(-100/h) = \n" ); document.write( "; \n" ); document.write( "2^(-100/h) = .61 \n" ); document.write( ": \n" ); document.write( "log(2^(-100/h)) = log(.61) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "h = \n" ); document.write( "h ~ 140 days is the half life \n" ); document.write( ": \n" ); document.write( "b. give a general formula that can be used to approximate the amount A of polonium after x days. \n" ); document.write( "A = 2*2^(-x/140) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "c. what is the half-life of the polonium? \n" ); document.write( "we found it to be 140 days in (a) \n" ); document.write( ": \n" ); document.write( " GRaph A(x) and show th epoint that would show the half-life for x=2 milligrams. \n" ); document.write( "Graph the equation y = 2*2^(-x/140) \n" ); document.write( " \n" ); document.write( "You can see that at 140 days there is about 1 mg of the substance \n" ); document.write( " \n" ); document.write( " |