document.write( "Question 270845: ichael discovers that the front car of a vintage roler caoster is a rectangular solid whose height is two feet shorter then its width and whose lenght is twice the width. the car has a volume of 150 cubic feet.
\n" ); document.write( "a) write an expression for the car's volume
\n" ); document.write( "b) write an equation showing that the car's volume is equal to 150. Rewrite this equation so thatone side is equal to 0. \n" ); document.write( "

Algebra.Com's Answer #198335 by Stitch(470) $\"\"$ $\"About$

You can put this solution on YOUR website!
When you read the problem you see that the dimensions are given in terms of the width. So let A = the width.
\n" ); document.write( "A(width) = X
\n" ); document.write( "B(height) = X-2
\n" ); document.write( "C(length) = 2X\r
\n" ); document.write( "\n" ); document.write( "A)The equation for the volume is A*B*C or $\"X%2A%28X-2%29%2A%282X%29\"$
\n" ); document.write( "B) $\"X%2A%28X-2%29%2A%282X%29+=+150\"$
\n" ); document.write( "C) $\"%28X%2A%28X-2%29%2A%282X%29%29+-+150+=+0\"$ \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"graph%28400%2C+300%2C+-20%2C+20%2C+-20%2C+20%2C+x%2A%28x-2%29%2A%282%2Ax%29-150%29\"$ \r
\n" ); document.write( "\n" ); document.write( "X = 5,
\n" ); document.write( "So with the width being 5ft, plug 5 into the equations for the height and length \n" ); document.write( "

\n" );