document.write( "Question 270827: the length of the rectangle is TWICE the width.
\n" ); document.write( "th length of the diagonal is 25cm\r
\n" ); document.write( "\n" ); document.write( "work out the area
\n" ); document.write( "give ur answer as an integer.
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Algebra.Com's Answer #198322 by JBarnum(2146)\"\" \"About 
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the length of the rectangle is TWICE the width. L=2W
\n" ); document.write( "the length of the diagonal is 25cm. C=25
\n" ); document.write( "LW=Area, 3W=Area
\n" ); document.write( "L^2+W^2=C^2
\n" ); document.write( "\"%282W%29%5E2%2BW%5E2=625\"
\n" ); document.write( "\"4W%5E2%2BW%5E2=625\"
\n" ); document.write( "\"5W%5E2%2F5=625%2F5\"
\n" ); document.write( "\"sqrt%28W%5E2%29=sqrt%28125%29\"
\n" ); document.write( "\"W=sqrt%28125%29\"
\n" ); document.write( "3w=Area
\n" ); document.write( "\"3%28sqrt%28125%29%29=A\"
\n" ); document.write( "\"33.541019662496845\"
\n" ); document.write( "\"highlight%2834cm%5E2%29\"\r
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