document.write( "Question 270821: how many liters of at 10% solution must be mixed with a 50% acid solution in order to obtain 30 liters of a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #198313 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many liters of at 10% solution must be mixed with a 50% acid solution in order to obtain 30 liters of a 30% solution? \n" ); document.write( "----------- \n" ); document.write( "One variable solution: \n" ); document.write( "Equation: \n" ); document.write( "active + active = active \n" ); document.write( "0.10x + 0.50(30-x) = 0.30*30 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "10x + 50*30 - 50x = 30*30 \n" ); document.write( "--- \n" ); document.write( "-40x = -20*30 \n" ); document.write( "x = 15 liters (amt. of 10% solution needed in the mixture) \n" ); document.write( "50-15 = 35 liters (amt. of 50% solution needed in the mixture)\r \n" ); document.write( "\n" ); document.write( "-------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |