document.write( "Question 270821: how many liters of at 10% solution must be mixed with a 50% acid solution in order to obtain 30 liters of a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #198313 by stanbon(75887)\"\" \"About 
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how many liters of at 10% solution must be mixed with a 50% acid solution in order to obtain 30 liters of a 30% solution?
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\n" ); document.write( "One variable solution:
\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.10x + 0.50(30-x) = 0.30*30
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "10x + 50*30 - 50x = 30*30
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\n" ); document.write( "-40x = -20*30
\n" ); document.write( "x = 15 liters (amt. of 10% solution needed in the mixture)
\n" ); document.write( "50-15 = 35 liters (amt. of 50% solution needed in the mixture)\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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