document.write( "Question 4356: solve the quadratic equation (x-3)squared=36 by the square root method. \n" ); document.write( "
Algebra.Com's Answer #1983 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"+%28x-3%29+%5E2+=+36\"\r
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\n" ); document.write( "\n" ); document.write( "Take the square root of both sides to \"undo\" the square.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt+%28%28x-3%29%5E2%29+=+0+%2B-+sqrt%2836%29\"
\n" ); document.write( "\"+x+-+3+=+0+%2B-+6\"\r
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\n" ); document.write( "\n" ); document.write( "To solve for x, add +3 to each side of the equation:
\n" ); document.write( "\"+x+-3+%2B+3+=+3+%2B-+6\"
\n" ); document.write( "\"x+=+3+%2B-+6\"\r
\n" ); document.write( "\n" ); document.write( "In the first case, this means x = 3 + 6, which is x = 9.
\n" ); document.write( "In the second case, this means x= 3 - 6, which is x = -3.\r
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\n" ); document.write( "\n" ); document.write( "Check your answers in the original equation:
\n" ); document.write( "\"+%28x-3%29+%5E2+=+36\"\r
\n" ); document.write( "\n" ); document.write( "For x = 9, \"+%289-3%29+%5E2+=+36\"\r
\n" ); document.write( "\n" ); document.write( "For x = -3, \"+%28-3-3%29+%5E2+=+36\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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