document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270712>Question 270712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i do 7r-5r+2=5r-r </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198296 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equation is:\r<BR>\n" );
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document.write( "7r-5r+2=5r-r\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "2r + 2 = 4r\r<BR>\n" );
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document.write( "subtract 2r from both sides of equation to get:\r<BR>\n" );
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document.write( "2 = 2r\r<BR>\n" );
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document.write( "divide both sides of equation by 2 to get r = 1\r<BR>\n" );
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document.write( "substitute in original equation to see if this is good.\r<BR>\n" );
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document.write( "original equation is:\r<BR>\n" );
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document.write( "7r-5r+2=5r-r\r<BR>\n" );
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document.write( "substitute 1 for r to get:\r<BR>\n" );
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document.write( "7 - 5 + 2 = 5 - 1 which becomes:\r<BR>\n" );
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document.write( "4 = 4 which is true, confirming that r = 1 is good.\r<BR>\n" );
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