document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270754>Question 270754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If line AC is tangent to circle O at point B , OC=65 and BC=60,What is the area of the square that would circumscribe the circle<BR>\n" );
document.write( "(heres a link to a diagram if you need it)<BR>\n" );
document.write( "http://www2.edmastery.com/files/nnds_prod_data/itemAssets/nnds_li%20-%20production%5Cjalberth%5C102.JPG </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198281 by </B><A HREF=/tutors/aboutme.mpl?userid=JBarnum><B>JBarnum(2146)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JBarnum><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JBarnum><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this really isnt that bad looks like...what??...but if u find the radius of the circle double it to make the diameter and then square the diameter u will get the area of a square that would enclose the circle.\r<BR>\n" );
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document.write( "so u have a triangle with 2 sides so u need to find the 3rd side using <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2%2BB%5E2=C%5E2 ALIGN=MIDDLE  ALT=\"A%5E2%2BB%5E2=C%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > according to the pic OC is the hypotenus we want to find OB<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2%2B60%5E2=65%5E2 ALIGN=MIDDLE  ALT=\"A%5E2%2B60%5E2=65%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2%2B3600=4225 ALIGN=MIDDLE  ALT=\"A%5E2%2B3600=4225\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2=4225-3600 ALIGN=MIDDLE  ALT=\"A%5E2=4225-3600\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28A%5E2%29=sqrt%28625%29 ALIGN=MIDDLE  ALT=\"sqrt%28A%5E2%29=sqrt%28625%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=25=OB ALIGN=MIDDLE  ALT=\"A=25=OB\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "so now the radius of the circle is 25 double it and then 2 it to find the area<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2825%2A2%29%5E2 ALIGN=MIDDLE  ALT=\"%2825%2A2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2850%29%5E2 ALIGN=MIDDLE  ALT=\"%2850%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%282500%29 ALIGN=MIDDLE  ALT=\"highlight%282500%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >is the area of the square. </SPAN>\n" );
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