document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270704>Question 270704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There were 200 tickets sold for Mr. Rustin. Tickets were $1.50 for students and $3.00 for adults. The total amount collected was $495. How many of each type of ticket were sold?\r<BR>\n" );
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document.write( "(Here is what I tried:)<BR>\n" );
document.write( "Variables:<BR>\n" );
document.write( "s= student tickets<BR>\n" );
document.write( "a=adult tickets\r<BR>\n" );
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document.write( "$1.50s+$3.00a=$495<BR>\n" );
document.write( "s+a=$200\r<BR>\n" );
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document.write( "I tried using the method of substitution but I can't seem to get to any solution. Could you please help me with this one?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198245 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There were 200 tickets sold for Mr. Rustin. Tickets were $1.50 for students and $3.00 for adults. The total amount collected was $495. How many of each type of ticket were sold? <BR>\n" );
document.write( "(Here is what I tried:)<BR>\n" );
document.write( "Variables:<BR>\n" );
document.write( "s= student tickets<BR>\n" );
document.write( "a=adult tickets <BR>\n" );
document.write( "$1.50s+$3.00a=$495<BR>\n" );
document.write( "s+a=$200 <BR>\n" );
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document.write( "What you have is the right approach, you were just one step away<BR>\n" );
document.write( "s + a = 200 (not dollars)<BR>\n" );
document.write( "--> s = 200 - a<BR>\n" );
document.write( "Then sub for s into the 1st eqn<BR>\n" );
document.write( "1.5(200-a) + 3a = 495<BR>\n" );
document.write( "300 + 1.5a = 495<BR>\n" );
document.write( "1.5a = 195<BR>\n" );
document.write( "a = 130<BR>\n" );
document.write( "s = 70<BR>\n" );
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