document.write( "Question 270675: A train traveled the first 1/6 of the distance from station A to station B at an average speed of 90 km/h, 2/3 of the distance at an average speed of 120 km/h, and the remaining 9 km at an average speed of 90 km/h. Find the average speed at which the train was traveling from station A to station B. \n" ); document.write( "
Algebra.Com's Answer #198240 by ptaylor(2198) You can put this solution on YOUR website! \n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "OK.\r \n" ); document.write( "\n" ); document.write( "We know that average speed or rate: r(av)=(total distance)/(total time) \n" ); document.write( "Let d=total distance from station A to Station B\r \n" ); document.write( "\n" ); document.write( "Then total time is the sum of the times listed below: \n" ); document.write( "time to travel 1/6 distance =(d/6)/90=d/540 \n" ); document.write( "time to travel 2/3 or 4/6 the distance=(4d/6)/120=d/180 \n" ); document.write( "time to travel the remaining 9 km=9/90=1/10\r \n" ); document.write( "\n" ); document.write( "Now lets look at what we have, first: \n" ); document.write( "1/6 of the distance plus 2/3 of the distance = 5/6 of the distance leaving 1/6 of the distance remaining which we are told is 9 km \n" ); document.write( "So, if (1/6)d=9, then the total distance (d)=54 km\r \n" ); document.write( "\n" ); document.write( "Therefore total time would be: \n" ); document.write( " 54/540 + 54/180 + 1/10 simplify \n" ); document.write( "1/10 + 27/90 +1/10 multiply each term by 90/90 \n" ); document.write( "9/90 +27/90 +9/90=45/90=1/2 hr\r \n" ); document.write( "\n" ); document.write( "So, Average Speed (rav)=54/(1/2)=108 km/hr\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |