document.write( "Question 270651: corporate investments The financial board of a corporation invested $25000 overseas, part at 4% and part at 7% annual interest.Find the amount invested at each rate if the first year combined income from the two investment was $1300 \n" ); document.write( "
Algebra.Com's Answer #198201 by Theo(13342)\"\" \"About 
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x = Amount of money invested at 4%
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\n" ); document.write( "\n" ); document.write( "Combined Interest = 1300\r
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\n" ); document.write( "\n" ); document.write( "Combined Interest Equation equals:\r
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\n" ); document.write( "\n" ); document.write( ".04*x + .07*y = 1300\r
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\n" ); document.write( "\n" ); document.write( "Total invested = 25,000\r
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\n" ); document.write( "\n" ); document.write( "Total Investment Equation equals:\r
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\n" ); document.write( "\n" ); document.write( "x + y = 25000\r
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\n" ); document.write( "\n" ); document.write( "You need to solve these two equations simultaneously to get your answer.\r
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\n" ); document.write( "\n" ); document.write( "The equations are:\r
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\n" ); document.write( "\n" ); document.write( "x + y = 25000
\n" ); document.write( ".04x + .07y = 1300\r
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\n" ); document.write( "\n" ); document.write( "use the first equation to solve for y in terms of x.\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "y = 25000 - x\r
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\n" ); document.write( "\n" ); document.write( "substitute for y in the second equation to get:\r
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\n" ); document.write( "\n" ); document.write( ".04x + .07(25000-x) = 1300\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( ".04x + .07*25000 - .07*x = 1300\r
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\n" ); document.write( "\n" ); document.write( "simplify further to get:\r
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\n" ); document.write( "\n" ); document.write( ".04x + 1750 - .07x = 1300\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "-.03x + 1750 = 1300\r
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\n" ); document.write( "\n" ); document.write( "subtract 1750 from both sides of equation to get:\r
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\n" ); document.write( "\n" ); document.write( "-.03x = 1300 - 1750 = -450\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of equation by -.03 to get:\r
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\n" ); document.write( "\n" ); document.write( "x = -450/-.03 = 150000\r
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\n" ); document.write( "\n" ); document.write( "since x + y = 2500, then y = 10000\r
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\n" ); document.write( "\n" ); document.write( "your answer should be:\r
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\n" ); document.write( "\n" ); document.write( "Amount invested at 4% = 15000.\r
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\n" ); document.write( "\n" ); document.write( "Amount invested at 7% = 10000.\r
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\n" ); document.write( "\n" ); document.write( "Interest on 15000 at 4% = .04 * 15000 = 600.\r
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\n" ); document.write( "\n" ); document.write( "Interest on 10000 at 7% = .07 * 10000 = 700.\r
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\n" ); document.write( "\n" ); document.write( "Combined interest = 600 + 700 = 1300, confirming the answer is good.\r
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