document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270620>Question 270620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor<BR>\n" );
document.write( "5x^2 + 34x + 24\r<BR>\n" );
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document.write( "This is what I have tried<BR>\n" );
document.write( "A=5, B=34, C=24<BR>\n" );
document.write( "AC=5*24=120<BR>\n" );
document.write( "I need to find the product of 120 and who sum is 34<BR>\n" );
document.write( "The numbers are 4 and 30, because 4*30=120 and 4+30=34<BR>\n" );
document.write( "replace middle term with 34x instead of 4x and 30x<BR>\n" );
document.write( "5x^2 + 34x +24 = (5x^2 + 4x)+ (30x + 24)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198198 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x^2 + 34x + 24 <BR>\n" );
document.write( "5*24=120; 2 factors of 120 whose sum is 34 are 4 & 30<BR>\n" );
document.write( "5x^2+30x+4x+24<BR>\n" );
document.write( "=5x(x+6)+4(x+6) factoring by grouping.<BR>\n" );
document.write( "=(5x+4)(x+6)<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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