document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270466>Question 270466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have apparently become to reliant on my calculator. I am not sure how to show the work for this problem. Can someone please help or get me headed in the right direction?\r<BR>\n" );
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document.write( "log 2x = log 3 + log (x - 4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198171 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log 2x = log 3 + log (x - 4)<BR>\n" );
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document.write( "Adding logs the same as multiply<BR>\n" );
document.write( "log(2x) = log(3(x-4))<BR>\n" );
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document.write( "log(2x) = log(3x-12)<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "2x = 3x - 12<BR>\n" );
document.write( "+12 = 3x - 2x<BR>\n" );
document.write( "12 = x<BR>\n" );
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document.write( "You can check it on your calc </SPAN>\n" );
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