document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270474>Question 270474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the circumference of an irregular shaped area, example a lawn, how do I calculate the sq ft ?. The circumferance is 320 ft </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198155 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If it is irregular the edge is the perimeter. It is only a circumference if you are dealing with a circle. If there are circular parts you may be able to calculate. If all else fails, draw out the plan on graph paper and count the squares </SPAN>\n" );
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