document.write( "Question 270415: For a normal probability distribution with a mean of 240 and a standard deviation of 40, calculate the following:
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document.write( "a. The probability that an observation will fall between 240 and 300.
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document.write( "b. The probability that an observation will fall between 195 and 240.
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document.write( "c. The probability that an observation will be less than 260.
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document.write( "d. The probability that an observation will fall between 180 and 220. \n" );
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Algebra.Com's Answer #198129 by stanbon(75887) ![]() You can put this solution on YOUR website! For a normal probability distribution with a mean of 240 and a standard deviation of 40, calculate the following: \n" ); document.write( "------- \n" ); document.write( "a. The probability that an observation will fall between 240 and 300. \n" ); document.write( "z(240) = (240-240)/40 = 0 \n" ); document.write( "z(300) = (300-240)/40 = 3/2 \n" ); document.write( "P(240< x <300) = P(0< z < 3/2) = 0.4332 \n" ); document.write( "----- \n" ); document.write( "Fallow the same procedure for b,c, and d. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "b. The probability that an observation will fall between 195 and 240. \n" ); document.write( "c. The probability that an observation will be less than 260. \n" ); document.write( "d. The probability that an observation will fall between 180 and 220. \n" ); document.write( " \n" ); document.write( " |