document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270355>Question 270355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> could you please help me solve this? I have no clue at all how to do this. <BR>\n" );
document.write( "Thanks\r<BR>\n" );
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document.write( "solve the system of linear equations using substitution:\r<BR>\n" );
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document.write( "y=2x<BR>\n" );
document.write( "y=-4x+8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #198085 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=198085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve the system of linear equations using substitution: <BR>\n" );
document.write( "y=2x<BR>\n" );
document.write( "y=-4x+8<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "Since they both equal y, sub for y in either equation.<BR>\n" );
document.write( "2x = -4x + 8<BR>\n" );
document.write( "6x = 8<BR>\n" );
document.write( "x = 4/3<BR>\n" );
document.write( "y = 8/3 </SPAN>\n" );
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