document.write( "Question 270275: A cross-country flight traveling with the wind covers 3000 miles in 5 hours. The same plane then changes direction and travels to Texas, against the wind, covering 1500 miles in 3 hours. What are the wind speed, and the speed of the plane in still air? \n" ); document.write( "
Algebra.Com's Answer #198049 by josmiceli(19441)\"\" \"About 
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Let \"p\" = plane's speed in still air
\n" ); document.write( "Let \"w\" = wind speed
\n" ); document.write( "Flying with the wind:
\n" ); document.write( "\"d%5B1%5D+=+%28p+%2B+w%29%2At%5B1%5D\"
\n" ); document.write( "Flying against the wind:
\n" ); document.write( "\"d%5B2%5D+=+%28p+-+w%29%2At%5B2%5D\"
\n" ); document.write( "-------------------------
\n" ); document.write( "given:
\n" ); document.write( "(1) \"3000+=+%28p+%2B+w%29%2A5\"
\n" ); document.write( "(2) \"1500+=+%28p+-+w%29%2A3\"
\n" ); document.write( "-------------------------
\n" ); document.write( "(1) \"5p+%2B+5w+=+3000\"
\n" ); document.write( "(2) \"3p+-+3w+=+1500\"
\n" ); document.write( "multiply both sides of (1) by \"3\"
\n" ); document.write( "and both sides of (2) by \"5\"
\n" ); document.write( "Then add the equations
\n" ); document.write( "(1) \"15p+%2B+15w+=+9000\"
\n" ); document.write( "(2) \"15p+-+15w+=+7500\"
\n" ); document.write( "\"30p+=+16500\"
\n" ); document.write( "\"p+=+550\" mi/hr
\n" ); document.write( "and, from (2)
\n" ); document.write( "(2) \"3p+-+3w+=+1500\"
\n" ); document.write( "\"3%2A550+-+3w+=+1500\"
\n" ); document.write( "\"1650+-+3w+=+1500\"
\n" ); document.write( "\"3w+=+1650+-+1500\"
\n" ); document.write( "\"3w+=+150\"
\n" ); document.write( "\"w+=+50\" mi/hr
\n" ); document.write( "the wind speed is 50 mi/hr
\n" ); document.write( "the plane's speed in still air is 550 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "(1) \"3000+=+%28p+%2B+w%29%2A5\"
\n" ); document.write( "\"3000+=+%28550+%2B+50%29%2A5\"
\n" ); document.write( "\"3000+=+600%2A5\"
\n" ); document.write( "\"3000+=+3000\"
\n" ); document.write( "(2) \"1500+=+%28p+-+w%29%2A3\"
\n" ); document.write( "\"1500+=+%28550+-+50%29%2A3\"
\n" ); document.write( "\"1500+=+500%2A3\"
\n" ); document.write( "\"1500+=+1500\"
\n" ); document.write( "OK \r
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