document.write( "Question 270229: how to change this to base 4?\r
\n" ); document.write( "\n" ); document.write( "log64 512
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Algebra.Com's Answer #198020 by CharlesG2(834)\"\" \"About 
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how to change this to base 4?
\n" ); document.write( "log64 512 \r
\n" ); document.write( "\n" ); document.write( "log64 512 = x (set it equal to x)
\n" ); document.write( "base b = 64
\n" ); document.write( "set y = 512
\n" ); document.write( "b^x = y --> 64^x = 512 --> 64 * 64^(1/2) = 512 --> x=3/2\r
\n" ); document.write( "\n" ); document.write( "logb (x) = logd (x) / logd (b) (d here is your new base)\r
\n" ); document.write( "\n" ); document.write( "4^0 = 1, 4^1 = 4, 4*4 = 16, 16*4 = 64, 64*4 = 256 , 256*2 = 512, 256 * 4 = 1024\r
\n" ); document.write( "\n" ); document.write( "log64 (512) = log4 (512) / log4 (64)
\n" ); document.write( "512/64 = 4^(4.5)/4^3 = 4*4*4*4*4^(1/2) / 4*4*4 = 4*4^(1/2) = 4^(3/2) = 8\r
\n" ); document.write( "\n" ); document.write( "log64 (512) = log4 (8) = 3/2\r
\n" ); document.write( "\n" ); document.write( "or 64^(3/2) = 512 and 4^(3/2) = 8\r
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