document.write( "Question 270225: mark was driving on a 245 miles trip. for the first 3 hours he traveled at a steady speed. at teh point realizing he would be late to his destination, he increased his speed by 10mph for the remaining 2 hours of the trip. what was his driving speed for each portion of the trip? \n" ); document.write( "
Algebra.Com's Answer #197997 by Stitch(470)\"\" \"About 
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Set-up:
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\n" ); document.write( "Mark drove for five hors total.
\n" ); document.write( "I wrote my equation in terms of his speed during the first three hours.
\n" ); document.write( "Equation:\"3%2AX+%2B+2%2A%28X%2B10%29+=+245\"\r
\n" ); document.write( "\n" ); document.write( "Solution:
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\n" ); document.write( "\"3%2AX+%2B+2%2A%28X%2B10%29+=+245\"Simplify
\n" ); document.write( "\"3X+%2B+2X+%2B+20+=+245\"Combine like terms
\n" ); document.write( "\"5X+%2B+20+=+245\"Subtract 20 from both sides
\n" ); document.write( "\"5X+=+225\" Divide both sides by 5
\n" ); document.write( "\"highlight%28X+=+45%29\"
\n" ); document.write( "So now we know that Mark was going 45mph during the fist three hours of the trip.
\n" ); document.write( "Then the problem states that during the remaining two hours he went 10mph faster. So during the last two hours of the trip Mark was going 55mph.\r
\n" ); document.write( "\n" ); document.write( "Check the answer:
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\n" ); document.write( "Plug the values back into the equation
\n" ); document.write( "\"3%2AX+%2B+2%2A%28X%2B10%29+=+245\"
\n" ); document.write( "\"3%2A%2845%29+%2B+2%2A%2855%29+=+245\"
\n" ); document.write( "\"135+%2B+110+=+225\"
\n" ); document.write( "\"highlight%28225+=+225%29\"
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