document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270200>Question 270200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat can travel 48 miles upstream (against the current) in the same amount of time that it takes to travel 72 miles downstream (with the current).  If the rate of the current is 4 miles per hour, what is the speed of the boat in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197978 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of the boat in still water=x<BR>\n" );
document.write( "The speed of the current = 4 m/h<BR>\n" );
document.write( "Given, the boat can travel 48 miles upstream (against the current) in the same amount of time that it takes to travel 72 miles downstream (with the current).<BR>\n" );
document.write( "So, 48/(x-4) = 72/(x+4)<BR>\n" );
document.write( "48(x+4) = 72(x-4)<BR>\n" );
document.write( "2(x+4)=3(x-4)<BR>\n" );
document.write( "2x+8=3x-12<BR>\n" );
document.write( "2x-3x=-12-8<BR>\n" );
document.write( "-x=-20<BR>\n" );
document.write( "x=20   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );