document.write( "Question 270124: If one professional roofer can roof and house in six days and another roofer can do it in 4 days how long does it take to roof the house together? \n" ); document.write( "
Algebra.Com's Answer #197954 by ptaylor(2198)\"\" \"About 
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Let x=amount of time needed if both roofers work together
\n" ); document.write( "So, together the two roofers work at the rate of 1/x roof per day
\n" ); document.write( "The first roofer works at the rate of 1/6 roof per day
\n" ); document.write( "The other roofer works at the rate of 1/4 roof per day
\n" ); document.write( "Our equation to solve, then is:
\n" ); document.write( "1/6 + 1/4 = 1/x multiply each term by 12x
\n" ); document.write( "2x+3x=12
\n" ); document.write( "5x=12
\n" ); document.write( "x=2.4 days------------------time needed when both are working together
\n" ); document.write( "CK
\n" ); document.write( "In 2.4 days, first roofer completes (2.4)/6 of the roof
\n" ); document.write( "In 2.4 days the other roofer completes (2.4)/4 of the roof
\n" ); document.write( "(2.4)/6 + (2.4)/4 should add up to 1 (1 roof, that is)
\n" ); document.write( "(4.8)/12 +(7.2)/12=12/12 or 1
\n" ); document.write( "1=1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "
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