document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=270162>Question 270162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maria has $1-coins and 50-centavos coins. If she has 3,600 coins in all, and amounting to $2250, how many coins of each kind does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197944 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Maria has $1-coins and 50-centavos coins. If she has 3,600 coins in all, and amounting to $2250, how many coins of each kind does she have?<BR>\n" );
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document.write( "One-variable solution:<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "100x + 50(3600-x) = 225000 centavos<BR>\n" );
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document.write( "100x + 180000 - 50x = 225000<BR>\n" );
document.write( "150x = 45000<BR>\n" );
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document.write( "x = 300 (# of $1 coins)<BR>\n" );
document.write( "3600-300 = 3300 (# of 50 centavos coins)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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