document.write( "Question 269969: rationalize denominator ___5__
\n" ); document.write( " sq rt 3\r
\n" ); document.write( "\n" ); document.write( " ___5___
\n" ); document.write( " 2+sq rt 3\r
\n" ); document.write( "\n" ); document.write( "I am not getting this...I have like five more...and I just need to see them worked out so I can finish this part. Much Mahalo.
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Algebra.Com's Answer #197919 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
We are trying to get an integer in the denominator so we will have a rational number, that is all. What can you multiply times the denominator to give an integer? 2-sqrt(3) in this case. (remember: (a-b)(a+b)=a^2-b^2
\n" ); document.write( "5/(2+sqrt(3)) * (2-sqrt(3))/(2-sqrt(3))
\n" ); document.write( "=5(2-sqrt(3))/(4-3)
\n" ); document.write( "=10-5sqrt(3)
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