document.write( "Question 270053: If we use values beyond our data set then
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document.write( " a. the predicted value can be wrong
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document.write( " b. the linear model may not fit the trend
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document.write( " c. A & B
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document.write( "9. When we find a variable that is statically significant
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document.write( " a. it allows us to build a model for estimating points
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document.write( " b. it can referred to as a “driver” of the change
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document.write( " c. A & B
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document.write( " d. it is important based on Bohme’s theory of significance
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document.write( "10.A point estimate for 8 units is
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document.write( "a. 8
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document.write( "b. 6.5
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document.write( "c. 7.36
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document.write( "11. A confidence interval for a sample average of 8 units
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document.write( "a. 4.72 to 9.56
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document.write( "b. 4.03 to 8.97
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document.write( "c. -1.05 to 14.05
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document.write( "d. 1.15 to 14.05\r
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document.write( "12. A confidence interval for a individual point of 8 units
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document.write( "a. 4.72 to 9.56
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document.write( "b. 4.03 to 8.97
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document.write( "c. -1.05 to 14.05
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document.write( "d. 1.15 to 14.05\r
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document.write( "
Algebra.Com's Answer #197880 by stanbon(75887) ![]() You can put this solution on YOUR website! The regression equation is \n" ); document.write( "Sales1 = - 0.86 + 0.920 Units\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Predictor Coef SE Coef T P \n" ); document.write( "Constant -0.864 3.265 -0.26 0.799 \n" ); document.write( "Units 0.9203 0.4219 2.18 0.066\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 3.76362 R-Sq = 40.5% R-Sq(adj) = 32.0%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Analysis of Variance\r \n" ); document.write( "\n" ); document.write( "Source DF SS MS F P \n" ); document.write( "Regression 1 67.40 67.40 4.76 0.066 \n" ); document.write( "Residual Error 7 99.15 14.16 \n" ); document.write( "Total 8 166.55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Unusual Observations\r \n" ); document.write( "\n" ); document.write( "Obs Units Sales1 Fit SE Fit Residual St Resid \n" ); document.write( " 1 12.4 17.10 10.55 2.55 6.55 2.37R \n" ); document.write( " 7 11.2 2.90 9.44 2.12 -6.54 -2.10R\r \n" ); document.write( "\n" ); document.write( "R denotes an observation with a large standardized residual.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Predicted Values for New Observations\r \n" ); document.write( "\n" ); document.write( "New \n" ); document.write( "Obs Fit SE Fit 90% CI 90% PI \n" ); document.write( " 1 6.50 1.31 (4.03, 8.97) (-1.05, 14.05)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Values of Predictors for New Observations\r \n" ); document.write( "\n" ); document.write( "New \n" ); document.write( "Obs Units \n" ); document.write( " 1 8.00\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we use values beyond our data set then \n" ); document.write( "a. the predicted value can be wrong \n" ); document.write( "b. the linear model may not fit the trend \n" ); document.write( "c. A & B \n" ); document.write( "Ans: c \n" ); document.write( "--------------------------------------------- \n" ); document.write( "9. When we find a variable that is statically significant \n" ); document.write( "a. it allows us to build a model for estimating points \n" ); document.write( "b. it can referred to as a “driver” of the change \n" ); document.write( "c. A & B \n" ); document.write( "d. it is important based on Bohme’s theory of significance \n" ); document.write( "Ans: I would say \"a\" \n" ); document.write( "---------------------------- \n" ); document.write( "10.A point estimate for 8 units is \n" ); document.write( "a. 8 \n" ); document.write( "b. 6.5 \n" ); document.write( "c. 7.36 \n" ); document.write( "Ans: Sales(8)=-.86 = 0.92*8 = 6.5 \n" ); document.write( "------------------------------------------------ \n" ); document.write( "11. A confidence interval for a sample average of 8 units \n" ); document.write( "a. 4.72 to 9.56 \n" ); document.write( "b. 4.03 to 8.97 \n" ); document.write( "c. -1.05 to 14.05 \n" ); document.write( "d. 1.15 to 14.05 \n" ); document.write( "Ans: 4.03 to 8.97 is the answer for either question 11 or question 12 \n" ); document.write( "I would have to read some text material to pin it down. \n" ); document.write( "------------------------------------ \n" ); document.write( "12. A confidence interval for a individual point of 8 units \n" ); document.write( "a. 4.72 to 9.56 \n" ); document.write( "b. 4.03 to 8.97 \n" ); document.write( "c. -1.05 to 14.05 \n" ); document.write( "d. 1.15 to 14.05 \n" ); document.write( "Ans: See answer to question 11 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |