document.write( "Question 269957: I am not understanding how to add polynomials that are in fraction form.\r
\n" ); document.write( "\n" ); document.write( "(-2)/(y^2-9) + (4y)/(y-3)^2 + (6)/(3-y)\r
\n" ); document.write( "\n" ); document.write( "I have never used this before so I hope the way I entered it makes sense. I really struggle with regular polynomials so this really throws me for a loop. Your help is appreciated. Thank you!
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Algebra.Com's Answer #197858 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
polynomials that are in fraction form.
\n" ); document.write( "\"%28-2%29%2F%28y%5E2-9%29\" + \"%284y%29%2F%28y-3%29%5E2\" + \"%286%29%2F%283-y%29\"
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\n" ); document.write( "Do some factoring, then determine a common denominator
\n" ); document.write( "\"%28-2%29%2F%28%28y-3%29%28y%2B3%29%29\" + \"%284y%29%2F%28%28y-3%29%28y-3%29%29\" + \"%286%29%2F%28-1%28y-3%29%29%29\"
\n" ); document.write( "that -1 with change the sign on the last fraction
\n" ); document.write( "\"%28-2%29%2F%28%28y-3%29%28y%2B3%29%29\" + \"%284y%29%2F%28%28y-3%29%28y-3%29%29\" - \"%286%29%2F%28%28y-3%29%29%29\"
\n" ); document.write( "the common denominator: (y-3)(y-3)(y+3)
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\n" ); document.write( "\"%28-2y%2B6+%2B+4y%5E2%2B12y-6%28y%5E2-9%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29\"
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\n" ); document.write( "\"%28%284y%5E2%2B10y-6y%5E2%2B6%2B54%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29\" = \"%28%28-2y%5E2%2B10y%2B60%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29\" = \"%28-2%28y%5E2-5y-30%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29\" = \"-%282%28y%5E2-5y-30%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29\"
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