document.write( "Question 269921: -8x+5y=3
\n" ); document.write( "Find the equation of line through 18,15 parallel to -8x+5y=3 and perpindicular.\r
\n" ); document.write( "\n" ); document.write( "I get the slope is 8/5 parallel and -5/8 perp, please help with the rest of the formula.There answer is (-5/8)x+(105/4) and -(-8/5)x+(-69/5). How are they getting the two answers?
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Algebra.Com's Answer #197854 by dabanfield(803)\"\" \"About 
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Find the equation of line through 18,15 parallel to -8x+5y=3 and perpindicular.
\n" ); document.write( "I get the slope is 8/5 parallel and -5/8 perp, please help with the rest of the formula.There answer is (-5/8)x+(105/4) and -(-8/5)x+(-69/5). How are they getting the two answers?\r
\n" ); document.write( "\n" ); document.write( "You have the two slopes right :)\r
\n" ); document.write( "\n" ); document.write( "The slope-intercept frm of the paralle line is:\r
\n" ); document.write( "\n" ); document.write( "y = (8/5)*x + b\r
\n" ); document.write( "\n" ); document.write( "Since the line passes through (18,15) we know when x = 18, y = 15 so:\r
\n" ); document.write( "\n" ); document.write( "15 = (8/5)*18 + b
\n" ); document.write( "b = 144/5 - 15
\n" ); document.write( "b = 144/5 - 75/18
\n" ); document.write( "b = 69/5 \r
\n" ); document.write( "\n" ); document.write( "So the parallel line is: y =(8/5)*x + 69/5\r
\n" ); document.write( "\n" ); document.write( "The perpendicular line is:\r
\n" ); document.write( "\n" ); document.write( "y = (-5/8)*x + b
\n" ); document.write( "15 = (-5/8)*18 + b
\n" ); document.write( "b = -90/8 - 15
\n" ); document.write( "b = -90/8 - 120/8
\n" ); document.write( "b = -210/8
\n" ); document.write( "b = -105/4\r
\n" ); document.write( "\n" ); document.write( "So the perpendicular line is: y = (-5/8)*x - 105/4
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