document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269990>Question 269990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cylindrical can of cleaner holds 1 L of liquid.  What is its height if the diameter of the base is 10 cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197847 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197847\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A cylindrical can of cleaner holds 1 L of liquid. What is its height if the diameter of the base is 10 cm?\r<BR>\n" );
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document.write( "The volume of a cylinder is area of the base x height. The radius of the base is 10/2 = 5cm. So, if h is the height we have:\r<BR>\n" );
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document.write( "pi*(5^2)*h = 1000 (remember 1L = 1000 cubic cm)\r<BR>\n" );
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document.write( "25*pi*h = 1000<BR>\n" );
document.write( "h = 1000/(25*pi) \r<BR>\n" );
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document.write( "Use 3.14 for the value of pi and complete the calculation above. </SPAN>\n" );
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