document.write( "Question 269966: Here is another one. Maybe once I get the hang of it I won't have to ask so many questions :)\r
\n" ); document.write( "\n" ); document.write( "(x^2)/(3x^2-5x-2) - (2x)/(3x+1) x (1)/(x-2)\r
\n" ); document.write( "\n" ); document.write( "The help is again appreciated. Some day I will have to understand this, I am sure it will be on a test! :) \n" ); document.write( "
Algebra.Com's Answer #197824 by dabanfield(803)\"\" \"About 
You can put this solution on YOUR website!
Here is another one. Maybe once I get the hang of it I won't have to ask so many questions :)
\n" ); document.write( "(x^2)/(3x^2-5x-2) - (2x)/(3x+1) x (1)/(x-2)
\n" ); document.write( "The help is again appreciated. Some day I will have to understand this, I am sure it will be on a test! :)\r
\n" ); document.write( "\n" ); document.write( "Using the rule that says (a/b)*(c/d) = (a*c)/(b*d) when we multiply out the expession on the right we then would have:\r
\n" ); document.write( "\n" ); document.write( "x^2/(3x^2-5x-2) - (2x*1)/[(3x+1)*(x-2)]\r
\n" ); document.write( "\n" ); document.write( "Multiplying out the denominator on the right we have:
\n" ); document.write( "x^2/(3x^2-5x-2) - 2x/(3x^2 - 6x + x -2) or
\n" ); document.write( "x^2/(3x^2-5x-2) - 2x(3x^2-5x-2)\r
\n" ); document.write( "\n" ); document.write( "Notice that each of these expressions has the same denominator so, using the rule that says a/b - c/b = (a-c)/b we have:\r
\n" ); document.write( "\n" ); document.write( "(x^2-2x)/(3x^2-5x-2)\r
\n" ); document.write( "\n" ); document.write( "Let's factor the numerator and denominator to see if we can simplify this?\r
\n" ); document.write( "\n" ); document.write( "[x*(x-2)]/[(3x+1)*(x-2)] \r
\n" ); document.write( "\n" ); document.write( "The factor x-2 cancels out so we have:\r
\n" ); document.write( "\n" ); document.write( "x/(3x+1)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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