document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269976>Question 269976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the problem 2y-8=x what is the next step to put it in slope intercept form? do you add the 8 to its self then add it to the x? then would it be 2y=x+8? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197812 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y-8=x<BR>\n" );
document.write( "2y=x+8<BR>\n" );
document.write( "now divide by 2<BR>\n" );
document.write( "y=1/2x+4<BR>\n" );
document.write( "----------\r<BR>\n" );
document.write( "\n" );
document.write( "slope m=1/2<BR>\n" );
document.write( "y int b=(0,4) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );