document.write( "Question 269809: A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing. \r
\n" ); document.write( "\n" ); document.write( "(a) How many different combinations of 3 cans could be selected? \r
\n" ); document.write( "\n" ); document.write( " Number of different combinations \r
\n" ); document.write( "\n" ); document.write( "(b) What is the probability that the contaminated can is selected for testing? (Round your answer to 3 decimal places.)
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\n" ); document.write( "\n" ); document.write( " Probability
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Algebra.Com's Answer #197783 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing.
\n" ); document.write( "(a) How many different combinations of 3 cans could be selected?
\n" ); document.write( "Number of different combinations.
\n" ); document.write( "24C3 = 2024
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\n" ); document.write( "(b) What is the probability that the contaminated can is selected for testing? (Round your answer to 3 decimal places.)
\n" ); document.write( "P(bad can included) = 1 - P(bad can not included)
\n" ); document.write( "= 1 - [23C3/24C3]
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\n" ); document.write( "= 1 - [1771/2024]
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\n" ); document.write( "= 0.125
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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