document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269911>Question 269911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (t/3 -2)=(3t/8)<BR>\n" );
document.write( "how do you solve?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197778 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (t/3 -2)=(3t/8)<BR>\n" );
document.write( "t/3-2=3t/8 subtract 3t/8<BR>\n" );
document.write( "t/3-3t/8=2 combine the fractions by finding the common denominator (3*8=24)<BR>\n" );
document.write( "(8*t-3*3t)/24=2 multiply the numerator terms. <BR>\n" );
document.write( "(8t-9t)/24=2 <BR>\n" );
document.write( "-t/24=2 cross multiply.<BR>\n" );
document.write( "-t=48<BR>\n" );
document.write( "t=-48 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "-48/3-2=3*-48/8<BR>\n" );
document.write( "-16-2=-144/8<BR>\n" );
document.write( "-18=-18\r<BR>\n" );
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