document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269915>Question 269915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of 2 supplementary angles are in the ratio 1:9. Find the degree measure of the smaller angle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197764 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1N+9N=180<BR>\n" );
document.write( "10N=180<BR>\n" );
document.write( "N=180/10<BR>\n" );
document.write( "N=18<BR>\n" );
document.write( "1*18=18 DEGREES FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "9*18=162 DEGREES FOR THE LARGER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "18 + 162 = 180<BR>\n" );
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