document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269799>Question 269799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me solve this expression.  25a^2 - 23a - 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197752 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25a^2-23a-2<BR>\n" );
document.write( "POSSIBLE FACTORS of 25 =1&25, -1&-25, 5&5, -5&-5<BR>\n" );
document.write( "POSSIBLE FACTORS of -2 =1&-2, 2&-1<BR>\n" );
document.write( "(25a-1)(a+2)=(25a^2-49a-2) not a solution.<BR>\n" );
document.write( "(5a-1)(5a+2)=(25a^2+5a-2) ditto.<BR>\n" );
document.write( "(-25a+1)(-a-2)=(25a^2+49a-2) ditto.<BR>\n" );
document.write( "(-5a+1)(-5a-2)=25a^2+5a-2) ditto<BR>\n" );
document.write( "(25a-2)(a+1)=(25a^2-23a-2) solution.<BR>\n" );
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