document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269891>Question 269891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If y=e^x (x-1)  then y''(0) equals\r<BR>\n" );
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document.write( "(A) -2<BR>\n" );
document.write( "(B) -1<BR>\n" );
document.write( "(C) 0<BR>\n" );
document.write( "(D) 1<BR>\n" );
document.write( "(E) none of these </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197738 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = (x-1)*e^x<BR>\n" );
document.write( "Take y' using the product rule and we get<BR>\n" );
document.write( "y' = (x-1)*e^x + e^x (1)<BR>\n" );
document.write( "take y''using the product rule and we get<BR>\n" );
document.write( "y'' = (x-1)*e^x + e^x + e^x<BR>\n" );
document.write( "Now y''(0) = (0-1)e^0 + e^0 + e^0 = -1 + 1 + 1 = 1<BR>\n" );
document.write( "This is answer choice (D) </SPAN>\n" );
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