document.write( "Question 269887: I have been trying to figure out this problem for an hour now I cannot get the answer the book gives me in the back. I found the problem here on your site already but the answers are not the same as the back of my book either.\r
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document.write( "This is the link to the problem on your site, http://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.164399.html\r
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document.write( "The problem is the same as in my book but the answers in the back say it should be : 2 hr at 50 mph and 3 hr at 40 mph.\r
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document.write( "I am so lost! \n" );
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Algebra.Com's Answer #197734 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! here is the original; problem \n" ); document.write( "\"a bus is traveling at 50 mph then reduces its speed to 40 mph. the 220 mi. trip takes 5 hrs. how long does it travel at each speed? show equation.\" \n" ); document.write( "This is an RTD problem. Here is a table based on the given information. \n" ); document.write( "bus . . . . . . . . .rate . . . . . . . . .time . . . . . . . . . distance \n" ); document.write( ". . . . . . . . . . . . 50 . . . . . . . . . . t . . . . . . . . . . . . .50t \n" ); document.write( ". . . . . . . . . . . . 40. . . . . . . . . 5 - t . . . . . . . . . . . 200 - 40t \n" ); document.write( ". . . . . . . . . . . . . . . . . . . . . . . .5. . . . . . . . . . . . . .220 \n" ); document.write( "from column 3 we get \n" ); document.write( "50t + 200 - 40t = 220 \n" ); document.write( "combine like terms and we get \n" ); document.write( "10t + 200 = 220 \n" ); document.write( "subtract to get \n" ); document.write( "10t = 20 \n" ); document.write( "t = 2 \n" ); document.write( "5 - t = 3 \n" ); document.write( "50 mph for 2 hours \n" ); document.write( "40 mph for 3 hours \n" ); document.write( " |