document.write( "Question 269883: What are three consecutive integers such that the sum of the first, twice the second, and three times the third is 80? \n" ); document.write( "

Algebra.Com's Answer #197719 by drk(1908) $\"\"$ $\"About$

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$\"x+%2B+2%2A%28x+%2B+1%29+%2B+3%2A%28x+%2B+2+%29+=+80\"$
\n" ); document.write( "distributing, we get
\n" ); document.write( " $\"x+%2B+2x+%2B+2+%2B+3x+%2B+6+=+80\"$
\n" ); document.write( "combine like terms, we get
\n" ); document.write( " $\"6x+%2B+8+=+80\"$
\n" ); document.write( "subtract 8 to get
\n" ); document.write( " $\"6x+=+72\"$
\n" ); document.write( "divide to get
\n" ); document.write( " $\"x+=+12\"$
\n" ); document.write( "the 3 numbers are 12, 13, 14 \n" ); document.write( "

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