document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269858>Question 269858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An urn contains 10 balls: 4 red and 6 blue. A second urn contains 16 red balls and an unknown number of blue balls. A single ball is drawn from each urn. The probability that both balls are the same colour is 0.44. Calculate the number of blue balls in the second urn. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197709 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of blue balls in the 2nd urn<BR>\n" );
document.write( "Total number of balls in 2nd urn is (16+x)\r<BR>\n" );
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document.write( "P1---Probability of drawing a blue ball in first urn is 6/10<BR>\n" );
document.write( "P2---Probability of drawing a blue ball in 2nd urn is x/(16+x)\r<BR>\n" );
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document.write( "Probability of P1 and P2 occurring together is P1*P2, so:\r<BR>\n" );
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document.write( "(6/10)(x/(16+x)=44/100  and this equals<BR>\n" );
document.write( "6x/10(16+x)=44/100  multiply each side by 100(16+x)<BR>\n" );
document.write( "60x=44(16+x) or<BR>\n" );
document.write( "60x=704+44x<BR>\n" );
document.write( "16x=704<BR>\n" );
document.write( "x=44---------------number of blue balls in 2nd urn<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "(6/10)(44/60)=44/100<BR>\n" );
document.write( "44/100 = 44/100\r<BR>\n" );
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document.write( "Does this help??---ptaylor </SPAN>\n" );
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